Test of significance: If this was a random sample from a larger population of 7th graders, let
\(\mu\) represent the mean number of push-ups that would be completed in this population. We want to decide whether
\(\mu\) is significantly different from 20.
\(H_0: \mu = 20\) (the population mean number of push-ups is 20)
\(H_a: \mu \neq 20\) (the population mean differs from 20)
Because we are working with a quantitative response variable and the sample size is large, we will model the sampling distribution of the standardized statistic with the
\(t\)-distribution with
\(80 - 1 = 79\) degrees of freedom.
\(t = \frac{15.49 - 20}{7.74/\sqrt{80}} = -5.21\) p-value =
\(2P(T_{79} < -5.21) = 2(0.0000007) = 0.0000014\)

\(t\)-distribution showing p-value area
With such a small p-value, we easily reject the null hypothesis and conclude that the population mean number of push-ups differs from 20.
To construct a 95% confidence interval for
\(\mu\text{,}\) we will use
\(t^*_{79} = 1.990\) \(\bar{x} \pm t^*_{79} \frac{s}{\sqrt{n}} = 15.49 \pm 1.990 \frac{7.74}{\sqrt{80}} \) \(= 15.49 \pm 1.72 = (13.76, 17.21)\)
Verifying these calculations with software, we would find:
R Output: \(\text{ }\) Answer.
JMP Output: \(\text{ }\) Answer.
Based on this sample, assuming it represents the larger population, we are 95% confident that the average number of push-ups completed by all 7th graders in the population is between 13.76 and 17.21, so 20 is rejected as a plausible value at the 0.05 level of significance. We could also find 99% and 99.9% confidence intervals for
\(\mu\) to be:
95%:
\(\bar{x} \pm t^*_{n-1} s/\sqrt{n} = 15.49 \pm 2.640(7.74/\sqrt{80})\)\(= 15.49 \pm 2.28 = (13.21, 17.77)\)
99%:
\(\bar{x} \pm t^*_{n-1} s/\sqrt{n} = 15.49 \pm 3.418(7.74/\sqrt{80})\)\(= 15.49 \pm 2.96 = (12.53, 18.45)\)
Thus, even with these stricter standards of 99% and 99.9% confidence, we still have reason to believe that the population mean is less than 20 push-ups. These results are consistent with the extremely small p-value from the significance test above.