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BHSawesome2 AP CSA Java 2025+

Section 2.22 Loops Coding Practice (2.7-2.12)

Activity 2.22.1.

Rewrite the following code so that it uses a for loop instead of a while loop to print out all the integers from 5 to 1 (inclusive).
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Solution.
Answer: In a for loop you declare and initialize the variable(s), specify the condition, and specify how the loop variable(s) change in the header of the for loop as shown below.
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public class Test1
{
    public static void main(String[] args)
    {
        for (int x = 5; x > 0; x = x - 1) System.out.println(x);
    }
}
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Activity 2.22.2.

Rewrite the following code to use a while loop instead of a for loop to print out the numbers from 1 to 10 (inclusive).
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Solution.
Answer: You need to specify the declarations and initializations of the loop variables(s) before the Boolean condition. You need to do the change(s) at the end of the body of the loop.
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public class Test1
{
    public static void main(String[] args)
    {
        int x = 1;
        while (x <= 10)
        {
            System.out.println(x);
            x++;
        }
    }
}
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Activity 2.22.3.

Rewrite the following code so that it uses a for loop instead of a while loop to print out all the integers from 5 to 15 (inclusive).
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Solution.
Answer: In a for loop you declare and initialize the variable(s), specify the condition, and specify how the loop variable(s) change in the header of the for loop as shown below.
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public class Test1
{
    public static void main(String[] args)
    {
        for (int x = 5; x <= 15; x++)
        {
            System.out.println(x);
        }
    }
}
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Activity 2.22.4.

Rewrite the following code to use a while loop instead of a for loop to print out the numbers from 10 to 100 by 10’s (inclusive).
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Solution.
Answer: You need to specify the declarations and initializations of the loop variables(s) before the Boolean condition. You need to do the change(s) at the end of the body of the loop.
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public class Test1
{
    public static void main(String[] args)
    {
        int x = 10;
        while (x <= 100)
        {
            System.out.println(x);
            x = x + 10;
        }
    }
}
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Activity 2.22.5.

The following code should print the values from 1 to 10 (inclusive) but has errors. Fix the errors so that the code works as intended. If the code is in an infinite loop you can refresh the page in the browser to stop the loop and then click on Load History and move the bar above it to see your last changes.
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Solution.
Answer: On line 6 it should be while (x <= 10). Add line 9 at the end of the loop body to increment x so that the loop ends (isn’t an infinite loop).
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public class Test1
{
    public static void main(String[] args)
    {
        int x = 1;
        while (x <= 10)
        {
            System.out.println(x);
            x++;
        }
    }
}
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Activity 2.22.6.

The following code should print the values from 10 to 5, but it has errors. Fix the errors so that the code works as intended.
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Solution.
Answer: Remove the x--; at the end of the body of the loop. The change area in the for loop decrements x by 1, so this line isn’t needed.
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public class Test1
{
    public static void main(String[] args)
    {
        for (int x = 10; x >= 5; x--)
        {
            System.out.println(x);
        }
    }
}
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Activity 2.22.7.

The following code should print the values from 10 to 1, but it has errors. Fix the errors so that the code works as intended.
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Solution.
Answer: Move the x--; to the end of the loop body (after the System.out.println. Change the while to x > 0.
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public class Test1
{
    public static void main(String[] args)
    {
        int x = 10;
        while (x > 0)
        {
            System.out.println(x);
            x--;
        }
    }
}
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Activity 2.22.8.

Finish the code below to print a countdown from 100 to 0 by 10’s using a for or while loop.
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Solution.
Answer: You can use a for loop as shown below. Start x at 100, loop while it is greater or equal to 0, and subtract 10 each time after the body of the loop executes.
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public class Test1
{
    public static void main(String[] args)
    {
        for (int x = 100; x >= 0; x = x - 10) System.out.println(x);
    }
}
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Activity 2.22.9.

Finish the code to print the value of x and " is even" if x is even and " is odd" if it is odd for all values from 10 to 1.
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Solution.
Answer: Use a for loop to loop from 10 to 1. Use a conditional to test if x is even (x % 2 == 0).
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public class Test1
{
    public static void main(String[] args)
    {
        for (int x = 10; x >= 1; x--)
        {
            if (x % 2 == 0)
            {
                System.out.println(x + " is even");
            }
            else
            {
                System.out.println(x + " is odd");
            }
        }
    }
}
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Activity 2.22.10.

Finish the code below to print the values for 10 * x where x changes from 0 to 10 using a loop.
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Solution.
Answer: Use a for loop with x changing from 0 to 10 and print the value of x and 10 * x.
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public class Test1
{
    public static void main(String[] args)
    {
        for (int x = 0; x <= 10; x++)
        {
            System.out.println(x * 10);
        }
    }
}
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Activity 2.22.11.

Finish the following code so that it prints a string message minus the last character each time through the loop until there are no more characters in message.
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Solution.
Answer: Add a while loop and loop while there is still at least one character in the string. At the end of the body of the loop reset the message to all characters except the last one.
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public class Test1
{
    public static void main(String[] args)
    {
        String message = "help";
        while (message.length() > 0)
        {
            System.out.println(message);
            message = message.substring(0, message.length() - 1);
        }
    }
}
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Activity 2.22.12.

Finish the code to loop printing the message each time through the loop and remove an x from the message until all the x’s are gone.
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Solution.
Answer: Use a while loop. Loop while x has been found in the message (using indexOf). Remove the x (using substring). Use indexOf again to get the position of the next x or -1 if there are none left in the message.
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public class Test1
{
    public static void main(String[] args)
    {
        String message = "Ix lovex youxxx";
        System.out.println(message);
        int pos = message.indexOf("x");
        while (pos >= 0)
        {
            message = message.substring(0, pos) + message.substring(pos + 1);
            pos = message.indexOf("x");
            System.out.println(message);
        }
    }
}
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Activity 2.22.13.

Write a loop below to print the number of x’s in the string message. Use the indexOf and substring methods.
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Solution.
Answer: Use indexOf to find the next x. Loop while pos is greater than or equal to 0. Use substring to reset message beyond the next x.
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public class Test1
{
    public static void main(String[] args)
    {

        String message = "xyxxzax";
        int pos = message.indexOf("x");
        int count = 0;
        while (pos >= 0)
        {
            count++;
            message = message.substring(pos + 1);
            pos = message.indexOf("x");
        }
        System.out.println("There were " + count + " x's");
    }
}
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Activity 2.22.14.

Write the code below to print a rectangle of stars (*) with 5 rows of stars and 3 stars per row. Hint: use nested for loops.
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Solution.
Answer: Use nested for loops. Use the outer loop to control the number of rows and the inner loop to control the number of stars per row.
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public class Test1
{
    public static void main(String[] args)
    {
        for (int row = 0; row < 5; row++)
        {
            for (int col = 0; col < 3; col++)
            {
                System.out.print("*");
            }
            System.out.println();
        }
    }
}
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Activity 2.22.15.

Write the code below to print a rectangle of stars (*) with 3 rows of stars and 5 stars per row.
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Solution.
Answer: Use nested for loops. Use the outer loop to control the number of rows and the inner loop to control the number of stars per row.
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public class Test1
{
    public static void main(String[] args)
    {
        for (int row = 0; row < 3; row++)
        {
            for (int col = 0; col < 5; col++)
            {
                System.out.print("*");
            }
            System.out.println();
        }
    }
}
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Activity 2.22.16.

Write the code below to print 55555, 4444, 333, 22, 1 with each on a different line.
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Solution.
Answer: Use nested for loops. The outer loop controls what is printed on each row and the number of rows. The inner loop controls the number of values printer per row.
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public class Test1
{
    public static void main(String[] args)
    {
        for (int x = 5; x >= 1; x--)
        {
            for (int y = x; y > 0; y--)
            {
                System.out.print(x);
            }
            System.out.println();
        }
    }
}
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