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COMP 1000: Think Like a Computer The PreTeXt Interactive Edition

Section 2.18 Chapter 2 Assessment

Check your understanding
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Checkpoint 2.18.1.

There is a function we are providing in for you in this problem called square. It takes one integer and returns the square of that integer value. Write code to assign a variable called xyz the value 5*5 (five squared). Use the square function, rather than just multiplying with *.
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Checkpoint 2.18.2.

Write code to assign the number of characters in the string rv to a variable num_chars.
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Checkpoint 2.18.3.

The code below initializes two variables, z and y. We want to assign the total number of characters in z and in y to the variable a. Which of the following solutions, if any, would be considered hard coding?
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z = "hello world"
y = "welcome!"
  • a = len("hello worldwelcome!")
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  • Though we are using the len function here, we are hardcoding what len should return the length of. We are not referencing z or y.
  • a = 11 + 8
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  • This is hardcoding, we are writing in the value without referencing z or y.
  • a = len(z) + len(y)
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  • This is not considered hard coding. We are using the function len to determine the length of what is stored in z and y, which is a correct way to approach this problem.
  • a = len("hello world") + len("welcome!")
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  • Though we are using the len function here, we are hardcoding what len should return the length of each time we call len. We are not referencing z or y.
  • none of the above are hardcoding.
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  • At least one of these solutions is considered hardcoding. Take another look.
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Checkpoint 2.18.4.

What does the code shown in the codelens image print when it finishes executing?
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  • an error
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  • This is a correct. When using + to stick strings together, all variables need to be a string. This throws a type error.
  • sara 11
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  • Hmm, this would be true if 11 was a string but it isn’t
  • sara11
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  • Hmm, not quite, we stick a space on our string in line 3
  • "sara11"
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  • Hmm, not quite, we stick a space on our string in line 3 and we don’t have quotes
  • "sara 11"
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  • Hmm, we don’t have quotes in our string
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Checkpoint 2.18.5. 

name = "sara"
age = 11
info = name + " " + str(age)
print(info)
Here is that same code again, but the error has been fixed. Which line number shows a line of code we would define as an expression?
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  • This is a variable being asssigned a string value
  • This is a variable being assigned an integer value
  • Correct, "sara" + " " + age is an expression that we want to evaluate to "sara 11" and store the string in the info variable
  • This prints the string value stored the info variable
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