SB Exercises

Exercises 9.22 Exercises

1.
Solution.

‘Python’[1] = ‘y’

‘Strings are sequences of characters.’[5] = ‘g’

len(‘wonderful’) = 9

‘Mystery’[:4] = ‘Myst’

‘p’ in ‘Pineapple’ = True

‘apple’ in ‘Pineapple’ = True

‘pear’ not in ‘Pineapple’ = True

‘apple’ > ‘pineapple’ = False

‘pineapple’ < ‘Peach’ = False
2.
In Robert McCloskey’s book Make Way for Ducklings, the names of the ducklings are Jack, Kack, Lack, Mack, Nack, Ouack, Pack, and Quack. This loop tries to output these names in order.

prefixes = "JKLMNOPQ" suffix = "ack" for p in prefixes: print(p + suffix)

Of course, that’s not quite right because Ouack and Quack are misspelled. Can you fix it?

prefixes = "JKLMNOPQ" suffix = "ack" for p in prefixes: print(p + suffix) # Fix the loop to get the correct output. ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): o = self.getOutput() code = self.getEditorText() self.assertIn("if", code, "Needs a conditional.") self.assertIn("for", code, "Needs a loop.") self.assertIn("Jack", o, "J + ack = Jack") self.assertIn("Kack", o, "K + ack = Kack") self.assertIn("Lack", o, "L + ack = Lack") self.assertIn("Mack", o, "M + ack = Mack") self.assertIn("Nack", o, "N + ack = Nack") self.assertIn("Ouack", o, "Don't forget the misspellings. Quack is required.") self.assertIn("Pack", o, "P + ack = Pack") self.assertIn("Quack", o, "Don't forget the misspellings. Quack is required.") self.assertNotIn("Oack", o, "Account for the misspellings. Qack should not be in output.") self.assertNotIn("Qack", o, "Account for the misspellings. Qack should not be in output.") myTests().main()
3.
Assign to a variable in your program a triple-quoted string that contains your favorite paragraph of text - perhaps a poem, a speech, instructions to bake a cake, some inspirational verses, etc.

Write a function that counts the number of alphabetic characters (a through z, or A through Z) in your text and then keeps track of how many are the letter ‘e’. Your function should print an analysis of the text like this:

Your text contains 243 alphabetic characters, of which 109 (44.8%) are 'e'.

def count(p): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): string1 = "e" string2 = "eieio" string3 = "eeeeeeeeeeee" string4 = "elephant" self.assertEqual(count(string1), 1, "Just one e") self.assertEqual(count(""), 0, "Empty string") self.assertEqual(count(string2), 2, "Two") self.assertEqual(count(string3), 12, "Twelve") self.assertNotEqual(count(string4), 3, "Has two Es") myTests().main()
Solution.
def count(p): lows = "abcdefghijklmnopqrstuvwxyz" ups = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" numberOfe = 0 totalChars = 0 for achar in p: if achar in lows or achar in ups: totalChars = totalChars + 1 if achar == 'e': numberOfe = numberOfe + 1 percent_with_e = (numberOfe / totalChars) * 100 print("Your text contains", totalChars, "alphabetic characters of which", numberOfe, "(", percent_with_e, "%)", "are 'e'.") p = ''' "If the automobile had followed the same development cycle as the computer, a Rolls-Royce would today cost $100, get a million miles per gallon, and explode once a year, killing everyone inside." -Robert Cringely ''' count(p)
4.

Print out a neatly formatted multiplication table, up to 12 x 12.
5.

Write a function that will return the number of digits in an integer.
def numDigits(n): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(numDigits(2),1,"Tested numDigits on input of 2") self.assertEqual(numDigits(55),2,"Tested numDigits on input of 55") self.assertEqual(numDigits(1352),4,"Tested numDigits on input of 1352") self.assertEqual(numDigits(444),3,"Tested numDigits on input of 444") myTests().main()
Solution.
def numDigits(n): n_str = str(n) return len(n_str) print(numDigits(50)) print(numDigits(20000)) print(numDigits(1))
6.

Write a function that reverses its string argument.
def reverse(astring): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(reverse("happy"),"yppah","Tested reverse on input of 'happy'") self.assertEqual(reverse("Python"),"nohtyP","Tested reverse on input of 'Python'") self.assertEqual(reverse(""),"","Tested reverse on input of ''") myTests().main()

7.

Solution.

from test import testEqual

def reverse(mystr):
    reversed = ''
    for char in mystr:
        reversed = char + reversed
    return reversed

def mirror(mystr):
    return mystr + reverse(mystr)

testEqual(mirror('good'), 'gooddoog')
testEqual(mirror('Python'), 'PythonnohtyP')
testEqual(mirror(''), '')
testEqual(mirror('a'), 'aa')

8.

Write a function that removes all occurrences of a given letter from a string.
def remove_letter(theLetter, theString): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(remove_letter("a","apple"),"pple","Tested remove_letter on inputs of 'a' and 'apple'") self.assertEqual(remove_letter("a","banana"),"bnn","Tested remove_letter on inputs of 'a' and 'banana'") self.assertEqual(remove_letter("z","banana"),"banana","Tested remove_letter on inputs of 'z' and 'banana'") myTests().main()
9.

Write a function that recognizes palindromes. (Hint: use your reverse function to make this easy!).
def is_palindrome(myStr): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(is_palindrome("abba"),True,"Tested is_palindrome on input of 'abba'") self.assertEqual(is_palindrome("abab"),False,"Tested is_palindrome on input of 'abab'") self.assertEqual(is_palindrome("straw warts"),True,"Tested is_palindrome on input of 'straw warts'") self.assertEqual(is_palindrome("a"),True,"Tested is_palindrome on input of 'a'") self.assertEqual(is_palindrome(""),True,"Tested is_palindrome on input of ''") myTests().main()
Solution.
from test import testEqual def reverse(mystr): reversed = '' for char in mystr: reversed = char + reversed return reversed def is_palindrome(myStr): if myStr in reverse(myStr): return True else: return False testEqual(is_palindrome('abba'), True) testEqual(is_palindrome('abab'), False) testEqual(is_palindrome('straw warts'), True) testEqual(is_palindrome('a'), True) testEqual(is_palindrome(''), True)
Write a function that counts how many non-overlapping occurences of a substring appear in a string.

def count(substr,theStr): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(count("is","Mississippi"),2,"Tested count on inputs of 'is' and 'Mississippi'") self.assertEqual(count("an","banana"),2,"Tested count on inputs of 'an' and 'banana'") self.assertEqual(count("ana","banana"),1,"Tested count on inputs of 'ana' and 'banana'") self.assertEqual(count("nana","banana"),1,"Tested count on inputs of 'nana' and 'banana'") self.assertEqual(count("nanan","banana"),0,"Tested count on inputs of 'nanan' and 'banana'") self.assertEqual(count("aaa","aaaaaa"),2,"Tested count on input of 'aaa' and 'aaaaaa'") myTests().main()
10.

Write a function that removes the first occurrence of a string from another string.
def remove(substr,theStr): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(remove("an","banana"),"bana","Tested remove on inputs of 'an' and 'banana'") self.assertEqual(remove("cyc","bicycle"),"bile","Tested remove on inputs of 'cyc' and 'bicycle'") self.assertEqual(remove("iss","Mississippi"),"Missippi","Tested remove on inputs of 'iss' and 'Mississippi'") self.assertEqual(remove("egg","bicycle"),"bicycle","Tested remove on inputs of 'egg' and 'bicycle'") myTests().main()
Solution.
from test import testEqual def remove(substr,theStr): index = theStr.find(substr) if index < 0: # substr doesn't exist in theStr return theStr return_str = theStr[:index] + theStr[index+len(substr):] return return_str testEqual(remove('an', 'banana'), 'bana') testEqual(remove('cyc', 'bicycle'), 'bile') testEqual(remove('iss', 'Mississippi'), 'Missippi') testEqual(remove('egg', 'bicycle'), 'bicycle')
11.

Write a function that removes all occurrences of a string from another string.
def remove_all(substr,theStr): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(remove_all("an","banana"),"ba","Tested remove_all on inputs of 'an' and 'banana'") self.assertEqual(remove_all("cyc","bicycle"),"bile","Tested remove_all on inputs of 'cyc' and 'bicycle'") self.assertEqual(remove_all("iss","Mississippi"),"Mippi","Tested remove_all on inputs of 'iss' and 'Mississippi'") self.assertEqual(remove_all("eggs","bicycle"),"bicycle","Tested remove_all on inputs of 'eggs' and 'bicycle'") myTests().main()

12.

Here is another interesting L-System called a Hilbert curve. Use 90 degrees:

L
L -> +RF-LFL-FR+
R -> -LF+RFR+FL-

Solution.

import turtle

def createLSystem(numIters, axiom):
    startString = axiom
    endString = ""
    for i in range(numIters):
        endString = processString(startString)
        startString = endString

    return endString

def processString(oldStr):
    newstr = ""
    for ch in oldStr:
        newstr = newstr + applyRules(ch)

    return newstr

def applyRules(ch):
    newstr = ""
    if ch == 'L':
        newstr = '+RF-LFL-FR+'   # Rule 1
    elif ch == 'R':
        newstr = '-LF+RFR+FL-'
    else:
        newstr = ch     # no rules apply so keep the character

    return newstr

def drawLsystem(aTurtle, instructions, angle, distance):
    for cmd in instructions:
        if cmd == 'F':
            aTurtle.forward(distance)
        elif cmd == 'B':
            aTurtle.backward(distance)
        elif cmd == '+':
            aTurtle.right(angle)
        elif cmd == '-':
            aTurtle.left(angle)

def main():
    inst = createLSystem(4, "L")  # create the string
    print(inst)
    t = turtle.Turtle()           # create the turtle
    wn = turtle.Screen()

    t.up()
    t.back(200)
    t.down()
    t.speed(9)
    drawLsystem(t, inst, 90, 5)   # draw the picture
                                  # angle 90, segment length 5
    wn.exitonclick()

main()

13.
Here is a dragon curve. Use 90 degrees.:

FX X -> X+YF+ Y -> -FX-Y

14.

Here is something called an arrowhead curve. Use 60 degrees.:

YF
X -> YF+XF+Y
Y -> XF-YF-X

Solution.

import turtle

def createLSystem(numIters, axiom):
    startString = axiom
    endString = ""
    for i in range(numIters):
        endString = processString(startString)
        startString = endString

    return endString

def processString(oldStr):
    newstr = ""
    for ch in oldStr:
        newstr = newstr + applyRules(ch)

    return newstr

def applyRules(ch):
    newstr = ""
    if ch == 'X':
        newstr = 'YF+XF+Y'   # Rule 1
    elif ch == 'Y':
        newstr = 'XF-YF-X'
    else:
        newstr = ch     # no rules apply so keep the character

    return newstr

def drawLsystem(aTurtle, instructions, angle, distance):
    for cmd in instructions:
        if cmd == 'F':
            aTurtle.forward(distance)
        elif cmd == 'B':
            aTurtle.backward(distance)
        elif cmd == '+':
            aTurtle.right(angle)
        elif cmd == '-':
            aTurtle.left(angle)

def main():
    inst = createLSystem(5, "YF")  # create the string
    print(inst)
    t = turtle.Turtle()            # create the turtle
    wn = turtle.Screen()

    t.speed(9)
    drawLsystem(t, inst, 60, 5)    # draw the picture
                                   # angle 90, segment length 5
    wn.exitonclick()

main()

15.

Try the Peano-Gosper curve. Use 60 degrees.:

FX
X -> X+YF++YF-FX--FXFX-YF+
Y -> -FX+YFYF++YF+FX--FX-Y

16.

The Sierpinski Triangle. Use 60 degrees.:
FXF--FF--FF
F -> FF
X -> --FXF++FXF++FXF--

Solution.

import turtle

def createLSystem(numIters, axiom):
    startString = axiom
    endString = ""
    for i in range(numIters):
        endString = processString(startString)
        startString = endString

    return endString

def processString(oldStr):
    newstr = ""
    for ch in oldStr:
        newstr = newstr + applyRules(ch)

    return newstr

def applyRules(ch):
    newstr = ""
    if ch == 'F':
        newstr = 'FF'   # Rule 1
    elif ch == 'X':
        newstr = '--FXF++FXF++FXF--'
    else:
        newstr = ch     # no rules apply so keep the character

    return newstr

def drawLsystem(aTurtle, instructions, angle, distance):
    for cmd in instructions:
        if cmd == 'F':
            aTurtle.forward(distance)
        elif cmd == 'B':
            aTurtle.backward(distance)
        elif cmd == '+':
            aTurtle.right(angle)
        elif cmd == '-':
            aTurtle.left(angle)

def main():
    inst = createLSystem(5, "FXF--FF--FF")   # create the string
    print(inst)
    t = turtle.Turtle()           # create the turtle
    wn = turtle.Screen()
    t.up()
    t.back(200)
    t.right(90)
    t.forward(100)
    t.left(90)
    t.down()
    t.speed(9)

    drawLsystem(t, inst, 60, 5)   # draw the picture
                                  # angle 90, segment length 5
    wn.exitonclick()

main()

17.

Write a function that implements a substitution cipher. In a substitution cipher one letter is substituted for another to garble the message. For example A -> Q, B -> T, C -> G etc. your function should take two parameters, the message you want to encrypt, and a string that represents the mapping of the 26 letters in the alphabet. Your function should return a string that is the encrypted version of the message.

18.

Write a function that decrypts the message from the previous exercise. It should also take two parameters. The encrypted message, and the mixed up alphabet. The function should return a string that is the same as the original unencrypted message.

Solution.

def encrypt(message, cipher):
    alphabet = "abcdefghijklmnopqrstuvwxyz"
    encrypted = ''
    for char in message:
        if char == ' ':
            encrypted = encrypted + ' '
        else:
            pos = alphabet.index(char)
            encrypted = encrypted + cipher[pos]
    return encrypted

def decrypt(encrypted, cipher):
    alphabet = "abcdefghijklmnopqrstuvwxyz"
    decrypted = ''
    for char in encrypted:
        if char == ' ':
            decrypted = decrypted + ' '
        else:
            pos = cipher.index(char)
            decrypted = decrypted + alphabet[pos]
    return decrypted


cipher = "badcfehgjilknmporqtsvuxwzy"

encrypted = encrypt('hello world', cipher)
print encrypted

decrypted = decrypt(encrypted, cipher)
print(decrypted)

19.

Write a function called remove_dups that takes a string and creates a new string by only adding those characters that are not already present. In other words, there will never be a duplicate letter added to the new string.
def remove_dups(astring): # your code here print(remove_dups("mississippi")) #should print misp ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(remove_dups("pooh"),"poh","Tested remove_dups on string 'pooh'") self.assertEqual(remove_dups("mississippi"),"misp","Tested remove_dups on string 'mississippi'") self.assertEqual(remove_dups("potato"),"pota","Tested remove_dups on string 'potato'") self.assertEqual(remove_dups("bookkeeper"),"bokepr","Tested remove_dups on string 'bookkeeper'") self.assertEqual(remove_dups("oo"),"o","Tested remove_dups on string 'oo'") myTests().main()
20.

Write a function called rot13 that uses the Caesar cipher to encrypt a message. The Caesar cipher works like a substitution cipher but each character is replaced by the character 13 characters to ‘its right’ in the alphabet. So for example the letter a becomes the letter n. If a letter is past the middle of the alphabet then the counting wraps around to the letter a again, so n becomes a, o becomes b and so on. Hint: Whenever you talk about things wrapping around its a good idea to think of modulo arithmetic.
def rot13(mess): # Your code here print(rot13('abcde')) print(rot13('nopqr')) print(rot13(rot13('Since rot13 is symmetric you should see this message')))
Solution.
def rot13(mess): alphabet = 'abcdefghijklmnopqrstuvwxyz' encrypted = '' for char in mess: if char == ' ': encrypted = encrypted + ' ' else: rotated_index = alphabet.index(char) + 13 if rotated_index < 26: encrypted = encrypted + alphabet[rotated_index] else: encrypted = encrypted + alphabet[rotated_index % 26] return encrypted print(rot13('abcde')) print(rot13('nopqr')) print(rot13(rot13('since rot thirteen is symmetric you should see this message')))
21.

Modify this code so it prints each subtotal, the total cost, and average price to exactly two decimal places.
def checkout(): total = 0 count = 0 moreItems = True while moreItems: price = float(input('Enter price of item (0 when done): ')) if price != 0: count = count + 1 total = total + price print('Subtotal: $', total) else: moreItems = False average = total / count print('Total items:', count) print('Total $', total) print('Average price per item: $', average) checkout()

You have attempted of activities on this page.

Prev Top Next

Exercises 9.22 Exercises

1.

2.

3.

4.

5.

6.

7.

8.

9.

10.

11.

12.

13.

14.

15.

16.

17.

18.

19.

20.

21.