14.15. Multiple Choice Questions

Q-1: Given the below html, how would this tag type be described in web scraping code?

<h1 class='sports'>Sports News</h1>

• h1
• Try again! Each tag must be in quotes and this answer does not mention the class attribute.
• h1, class='sports'
• Try again! Each tag must be in quotes and the class has to be followed by an underscore.
• h1, class_='sports'
• Try again! Each tag must be in quotes.
• 'h1', class_='sports'
• Correct! Both the tag and attribute are important. The h1 tag needs to be in quotes, and class has to be followed by an underscore.

Q-2: Which line of code correctly gets the first item in items and makes the most sense following the below code snippet?

soup = BeautifulSoup(response.content, 'html.parser')
items = soup.find_all(class_='items')

• first_item = items[0]
• Correct! Given that soup.find_all(class_='items') returns a list, in order to get the first item, all you need to do is index.
• first_item = items.find(0)
• Try again! Since soup.find_all(class_='items') returns a list, we cannot use find() as it is a string method that returns the first instance of a specified value in a string.
• first_item = items.get(0)
• Try again! Since soup.find_all(class_='items') returns a list, we cannot use get() as it is a dictionary method used to return the value of an item with specified key.
• first_item = items.find[0]
• Try again! Since soup.find_all(class_='items') returns a list, we cannot use find() as it is a string method that returns the first instance of a specified value in a string.
• first_item = soup.items[0]
• Try again! We already called the soup object to get items so all we need to do is index to the first item.

Q-3: How does one parse the HTML into a BeautifulSoup object given a response object?

• soup = BeautifulSoup(response.text, 'html.parser')
• Correct! It is the correct way to parse content in UniCode.
• soup = BeautifulSoup(response.content, 'html.parser')
• Correct! It is the correct way to parse content in bytes.
• soup = BeautifulSoup(response.string, 'html.parser')
• Try again! .string returns None if there is more than one tag inside of the ``response`` object.

Q-4: Which of the following is the best way to get the value for the id in the first p tag?

• soup.p.get('id')
• Try again! If there is no tag 'id', this line will return an error.
• soup.p.get('id', None)
• Correct! This is the correct way to get the first p tag and get the value for the id in the p tag.
• soup.p[id]
• Try again! The correct way to find a tag is to use the get method().
• soup.p['id']
• Try again! The correct way to find a tag is to use the get method().

Q-5: How does one get the first header 1 tag after creating a soup object?

• soup.h1
• Correct! The header 1 tag is h1, and this is the correct way to get the first header 1 tag after creating a soup object.
• soup.header1
• Try again! There is no tag called header1.
• soup.h1[0]
• Try again! h1 is a tag and index 0 will not give the correct output.
• soup.h1[1]
• Try again! h1 is a tag and index 1 will not give the correct output.

Q-6: Which of the following gets the first link tag and returns a dictionary of all attributes and values for that link tag?

• soup.a.attributes
• Try again! Attributes is not the correct way to get a dictionary of all attributes and values for a tag.
• soup.link.attrs
• Try again! There is no tag 'link', instead we use tag 'a' to find links.
• soup.a.attrs
• Correct! This is the correct way to get the first link tag (soup.a) and get a dictionary of all attributes and values for that link tag (.attrs).
• soup.link.attributes
• Try again! There is no tag 'link', instead we use tag 'a' to find links. Attributes is not the correct way to get a dictionary of all attributes and values for a tag.

Q-7: Which of the following finds all link tags?

• all_links = soup.find('a')
• Try again! This will only find the first link.
• all_links = soup.findall('a')
• Try again! For Beautiful Soup, find_all requires an underscore.
• all_links = soup.findall('link')
• Try again! For Beautiful Soup, find_all requires an underscore. There is no tag called 'link'.
• all_links = soup.find_all('a')
• Correct! This is the correct way to find all link tags. In HTML, link tags are 'a' tags. For Beautiful Soup, find_all requires an underscore.
• all_links = soup.find_all('link')
• Try again! There is no tag called 'link', instead we use tag 'a' to get links.

Q-8: Which of the following finds all paragraph tags with class b-soup?

• all_links = soup.find_all('p', class='b-soup')
• Try again! To find a class in Beautiful Soup, it requires an underscore (class_).
• all_links = soup.find_all('paragraph', class='b-soup')
• Try again! There is no tag called 'paragraph', instead we use tag 'p' to find paragraphs. Also, to find a class in Beautiful Soup, it requires an underscore (class_).
• all_links = soup.find_all('p', class_='b-soup')
• Correct! This is the correct way to find all paragraph tags. In HTML, paragraph tags are 'p' tags. For Beautiful Soup, to find a class, class requires an underscore (class_).
• all_links = soup.find_all('paragraph', class_='b-soup')
• Try again! There is no tag called 'paragraph', instead we use tag 'p' to find paragraphs.

Q-9: After creating an empty dictionary and getting a list of all link tags, how does one put the link_tag text as keys and the link_tag href attribute as values for the dictionary?

• loop through the elements of the list and do dictionary[link_tag.text] = a.get('href', None)
• Try again! Although the 'a' tag is the link tag, the variable that contains the href attribute is link_tag.
• loop through the elements of the list and do dictionary[link_tag.text] = a['href']
• Try again! Although the 'a' tag is the link tag, the variable that contains the href attribute is link_tag. Also, using the format tag['attribute_name'] will cause an error if the tag is not there.
• loop through the elements of the list and do dictionary[link_tag.text] = link_tag.get('href', None)
• Correct! This is the correct way to create a dictionary with link_tag text as keys and href as values. Using .get('attribute_name', None) will not cause an error. It will set None as the default value and grab the value if there is one.
• loop through the elements of the list and do dictionary[link_tag.text] = link_tag[href]
• Try again! The attribute name is missing quotation marks, and using the format tag['attribute_name'] will cause an error if the tag is not there.

Q-10: Given the below html, after importing re, what will be returned after for tag in soup.find_all(re.compile("t")): print(tag.name) is run?

<html>
   <head>
      <title>Site</title>
   </head>
   <body>
      <p>There is lots of content.</p>
   </body>
</html>

• html
• Correct! It returns html as it is the name of a tag that contains the letter 't'.
• title
• Correct! It returns title as it is the name of a tag that contains the letter 't'.
• Site
• Try again! 'Site' is not a tag.
• There is lots of content.
• Try again! This isn't a tag. This is the content inside a 'p' tag.

Q-11: What does the following block of code do?

url = "https://www.nytimes.com"
html = urllib.request.urlopen(url, context=ctx).read()
soup = BeautifulSoup(html, 'html.parser')

• retrieves and displays the webpage
• Try Again! This does not display the webpage. BeautufulSoup parses webpage retrieved by urllib.rquest.
• parses the html content of the "https://www.nytimes.com" webpage.
• Correct! This parses all html tags and contents of the webpage.
• downloads the webpage
• Try Again! This does not save files to the computer.

Q-12: What does the following block of code print?

url = "https://www.nytimes.com/"
html = urllib.request.urlopen(url).read()
soup = BeautifulSoup(html, 'html.parser')

tags = soup('img')
for tag in tags:
    print(tag.get('src', None))

• retrieves and displays the webpage
• Try Again! Urllib retrieves the webpage but does not display it.
• downloads the webpage
• Try Again! This does not save files to the computer.
• prints the images from 'www.nytimes.com'
• Try Again! BeautifulSoup and html.parser cannot display images
• prints all the 'img' sources under 'src' from 'www.nytimes.com'
• Correct! It prints out the image sources listed under 'src' of 'img' tags.

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