TCPP2 The printDeck function

Section 12.7 The printDeck function

Whenever you are working with vectors, it is convenient to have a function that prints the contents of the vector. We have seen the pattern for traversing a vector several times, so the following function should be familiar:

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Listing 12.7.1. Printing a Deck

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void printDeck(const vector<Card>& deck) {
      for (size_t i = 0; i < deck.size(); i++) {
        deck[i].print();
      }
    }

By now it should come as no surprise that we can compose the syntax for vector access with the syntax for invoking a function.

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Since deck has type vector<Card>, an element of deck has type Card. Therefore, it is legal to invoke print on deck[i].

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Checkpoint 12.7.1.

A Euchre Deck contains 9’s, 10’s, Jacks, Queens, Kings, and Aces of all four suits. Modify the buildDeck function below to create a Euchre deck. The printDeck function will allow you to verify that you have done this correctly.

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#include <iostream>
#include <string>
#include <vector>
using namespace std;

struct Card {
    int suit, rank;

Card();
    Card(int s, int r);
    void print() const;
};

vector<Card> buildDeck() {
    vector<Card> deck(52);
    int i = 0;
    for (int suit = 0; suit <= 3; suit++) {
        for (int rank = 1; rank <= 13; rank++) {
            deck[i].suit = suit;
            deck[i].rank = rank;
            i++;
        }
    }
    return deck;
}

void printDeck(const vector<Card>& deck);

int main() {
    vector<Card> deck = buildDeck();
    printDeck(deck);
}
====
Card::Card() {
   suit = 0;  rank = 0;
}

Card::Card(int s, int r) {
   suit = s;  rank = r;
}

void Card::print() const {
   vector<string> suits(4);
   suits[0] = "Clubs";
   suits[1] = "Diamonds";
   suits[2] = "Hearts";
   suits[3] = "Spades";

vector<string> ranks(14);
   ranks[1] = "Ace";
   ranks[2] = "2";
   ranks[3] = "3";
   ranks[4] = "4";
   ranks[5] = "5";
   ranks[6] = "6";
   ranks[7] = "7";
   ranks[8] = "8";
   ranks[9] = "9";
   ranks[10] = "10";
   ranks[11] = "Jack";
   ranks[12] = "Queen";
   ranks[13] = "King";

cout << ranks[rank] << " of " << suits[suit] << endl;
 }

void printDeck(const vector<Card>& deck) {
   for (size_t i = 0; i < deck.size(); i++) {
     deck[i].print();
   }
 }

Solution.

Hopefully you took some time to try and figure out the code yourself. The solution below is just one of several correct solutions for creating the Euchre deck:

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vector<Card> buildEuchreDeck() {
      vector<Card> deck(24);
      int i = 0;
      for (int suit = 0; suit <= 3; suit++) {
          for (int rank = 1; rank <= 13; rank++) {
            if (rank == 1 || rank >= 9) {
              deck[i].suit = suit;
              deck[i].rank = rank;
              i++;
            }
          }
      }
      return deck;
    }

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How To Think Like a Computer Scientist C++ Edition The Pretext Interactive Version

Section 12.7 The `printDeck` function

Checkpoint 12.7.1.

Section 12.7 The printDeck function

Checkpoint 12.7.1.

Section 12.7 The `printDeck` function