Before you keep reading...

Runestone Academy can only continue if we get support from individuals like you. As a student you are well aware of the high cost of textbooks. Our mission is to provide great books to you for free, but we ask that you consider a $10 donation, more if you can or less if $10 is a burden.

Support Runestone Academy Today

Before you keep reading...

Making great stuff takes time and $$. If you appreciate the book you are reading now and want to keep quality materials free for other students please consider a donation to Runestone Academy. We ask that you consider a $10 donation, but if you can give more thats great, if $10 is too much for your budget we would be happy with whatever you can afford as a show of support.

Support Runestone Academy Today

15.3. Looping through nodes

Often the XML has multiple nodes and we need to write a loop to process all of the nodes. In the following program, we loop through all of the user nodes:

What do you think this code will print? Run it to see what it actually prints.

import xml.etree.ElementTree as ET input = ''' <stuff> <users> <user x="2"> <id>001</id> <name>Chuck</name> </user> <user x="7"> <id>009</id> <name>Brent</name> </user> </users> </stuff>''' stuff = ET.fromstring(input) lst = stuff.findall('users/user') print('User count:', len(lst)) for item in lst: print('Name', item.find('name').text) print('Id', item.find('id').text) print('Attribute', item.get('x'))

The findall method retrieves a Python list of subtrees that represent the user structures in the XML tree. Then we can write a for loop that looks at each of the user nodes, and prints the name and id text elements as well as the x attribute from the user node.

Put the following blocks in order to use a loop to process nodes in an XML program, like the one seen above.

        Use findall to retrieve subtrees representing user structures in the XML tree.
---
Use a for each loop to loop through the user nodes
---
    Print the name and id from the user node
---
    Print the x attribute from the user node using get
        

It is important to include all parent level elements in the findall statement except for the top level element (e.g., users/user). Otherwise, Python will not find any desired nodes.

What do you think this code will print? Run it to see what it actually prints.

import xml.etree.ElementTree as ET input = ''' <stuff> <users> <user x="2"> <id>001</id> <name>Chuck</name> </user> <user x="7"> <id>009</id> <name>Brent</name> </user> </users> </stuff>''' stuff = ET.fromstring(input) lst = stuff.findall('users/user') print('User count:', len(lst)) lst2 = stuff.findall('user') print('User count:', len(lst2))

lst stores all user elements that are nested within their users parent. lst2 looks for user elements that are not nested within the top level stuff element where there are none.

You have attempted of activities on this page