10.4. Looping and Dictionaries¶
If you use a dictionary as the sequence in a for
statement,
it traverses the keys of the dictionary. This loop prints each key and
the corresponding value:
counts = { 'chuck' : 1 , 'annie' : 42, 'jan': 100}
for key in counts:
print(key, counts[key])
Here’s what the output looks like:
jan 100
chuck 1
annie 42
Again, the keys are in no particular order.
We can use this pattern to implement the various loop idioms that we have described earlier. For example if we wanted to find all the entries in a dictionary with a value above ten, we could write the following code:
counts = { 'chuck' : 1 , 'annie' : 42, 'jan': 100}
for key in counts:
if counts[key] > 10 :
print(key, counts[key])
The for
loop iterates through the keys of
the dictionary, so we must use the index operator to retrieve the
corresponding value for each key. Here’s what the output
looks like:
jan 100
annie 42
We see only the entries with a value above 10.
- ['NBA Champ', 'Finals MVP', 'MVP', 'All-Star']
- Try again! This list does not inlude all the values that are greater than or equal to one.
- ['NBA Champ', 'Finals MVP', 'MVP', 'All-Star', 'ROTY']
- Correct! This code takes the keys with values greater than or equal to one and puts them into a list. If any of you are wondering, these are some of LeBron James' accolades.
- ['MVP', 'All-Star']
- Try again! This list does not inlude all the values that are greater than or equal to one.
Q-1: What is printed after the following code is run?
counts = {'NBA Champ': 3, 'MVP': 4, 'All-Star': 16, 'ROTY': 1, '6MOTY': 0}
counts['Finals MVP'] = 3
achievements = []
for achievement in counts:
if counts[achievement] >= 1:
achievements.append(achievement)
print(achievements)
If you want to print the keys in alphabetical order, you first make a
list of the keys in the dictionary using the keys
method
available in dictionary objects, and then sort that list and loop
through the sorted list, looking up each key and printing out key-value
pairs in sorted order as follows:
counts = { 'chuck' : 1 , 'annie' : 42, 'jan': 100}
lst = list(counts.keys())
print(lst)
lst.sort()
for key in lst:
print(key, counts[key])
Here’s what the output looks like:
['jan', 'chuck', 'annie']
annie 42
chuck 1
jan 100
First you see the list of keys in unsorted order that we get from the
keys
method. Then we see the key-value pairs in order from
the for
loop.
Write code to add the keys of dictionary wordCount into a list named MoreThan5 if the keys’ value is greater than 5.
Construct a block of code that adds the items in a dictionary to a list, where the items’ values are greater than or equal to 8, and prints said list.