10.8. Multiple Choice Questions¶
- fruits['grapes']
- Try again! This does not add a value.
- fruits['grapes'] = 15
- Correct! This line adds 'grapes' as a key with a value of 15.
- insert 'grapes' in fruits
- Try again! This is not correct Python.
- fruits[15] = 'grapes'
- Try again! This sets the key to 15 and the value to 'grapes'.
Q-1: Which line of code correctly adds an item to the fruits
dictionary with a key of ‘grapes’ and a value of 15?
fruits = {'apples': 1, 'bananas': 4, 'pears': 17, 'oranges': 14}
- ['Janice', 'John']
- Try again! This would be true if it was greater than or equal 5.
- ['Janice', 'Emily', 'Eleanor']
- Try again! This only adds items with a value greater than 5.
- ['John']
- Correct! John is the only key that has a value greater than 5.
- ['Janice', 'Emily', 'John', 'Eleanor']
- Try again! This only adds items with a value greater than 5.
Q-2: What does the following code print?
names = {'Janice': 5, 'Emily': 3, 'John': 7, 'Eleanor': 2}
list_o_names = []
for name in names:
if names[name] > 5:
list_o_names.append(name)
print(list_o_names)
- ['Emily', 'John', 'Erik']
- Correct! Erik is initialized to 22, and Emily is updated to 13. Therefore, these two entries are added to the list found in the previous question.
- ['Janice', 'Emily', 'John']
- Try again! Erik is set to 22, so it should be added.
- ['Janice', 'John', 'Erik']
- Try again! Emily is set to 13, so it should be added.
- ['Janice', 'Emily', 'John', 'Eleanor']
- Try again! This will not add Eleanor since the value is 2, and this will not add Janice since the value is 5.
Q-3: What does the following code print?
names = {'Janice': 5, 'Emily': 3, 'John': 7, 'Eleanor': 2}
list_o_names = []
names['Emily'] += 10
names['Erik'] = 22
for name in names:
if names[name] > 5:
list_o_names.append(name)
print(list_o_names)
- 5
- Try again!
- 10
- Try again!
- 9
- Correct! There are 9 letters in phrase that appear more than two times.
Q-4: What is the value of counter
after the code is run?
phrase = "Cheese in Philadelphia is extraordinary according to Erik"
counter = 0
letters = {}
for word in phrase.split():
for letter in word:
letter = letter.lower()
if letter not in letters.keys():
letters[letter] = 0
letters[letter] += 1
for key in letters.keys():
if letters[key] > 2:
counter += 1
- fruits.get(apples)
- Try again! The key must be a string in this case.
- fruits.get('apples', 0)
- Correct! This correctly grabs the key as a string and also includes a default value in case the key is not present in the dictionary.
- fruits.get('apple')
- Try again! This will return None if the key does not exist.
- fruits.get(apples, 0)
- Try again! The key must be a string in this case.
Q-5: Which line of code correctly gets the value of the key ‘apples’ if it exists and returns 0 if it does not?
fruits = {'bananas': 7, 'apples': 4, 'grapes': 19, 'pears': 4}
- 10
- Try again!
- 4
- Try again!
- 6
- Correct! The get() method grabs the value 2 and then 4 gets added to it to get 6.
- 2
- Try again! This would be true if it just printed the value for the key 'o'. However, 4 is added to it.
Q-6: What value is printed when this code runs?
word = 'brontosaurus'
diction = {}
for letter in word:
if letter not in diction.keys():
diction[letter] = 0
diction[letter] += 1
print(diction.get('o', 0) + 4)
- jan, chuck, annie
- The order is their order in the dictionary.
- chuck, annie, jan
- The order is their order in the dictionary.
- annie, chuck, jan
- Correct! The order is their order in the dictionary.
- jan, annie, chuck
- The order is their order in the dictionary.
Q-7: What order do the keys print in after the following code is run?
counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}
for key in counts:
print(key)
- jan, chuck, annie
- Correct! This will sort by the keys in descending order.
- chuck, annie, jan
- This will sort by the keys in descending order.
- annie, chuck, jan
- This will sort by the keys in descending order.
- jan, annie, chuck
- This will sort by the keys in descending order.
Q-8: What order do the keys print in after the following code is run?
counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}
items = counts.items()
out = sorted(items, reverse = True)
for item in out:
print(item[0])
- jan, chuck, annie
- This will sort by the values in ascending order.
- chuck, annie, jan
- Correct! This will sort by the values in ascending order.
- annie, chuck, jan
- This will sort by the values in ascending order.
- jan, annie, chuck
- This will sort by the values in ascending order.
Q-9: What order do the keys print in after the following code is run?
counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}
items = counts.items()
out = sorted(items, key = lambda t: t[1])
for item in out:
print(item[0])
- jan, chuck, annie
- This will print the keys in their current order since sorted returns a new list.
- chuck, annie, jan
- This will print the keys in their current order since sorted returns a new list.
- annie, chuck, jan
- Correct! This will print the keys in their current order since sorted returns a new list.
- jan, annie, chuck
- This will print the keys in their current order since sorted returns a new list.
Q-10: What order do the keys print in after the following code is run?
counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}
items = counts.items()
sorted(items, key = lambda t: t[1])
for item in items:
print(item[0])
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