In the previous example, we wrote a function that computes the square of a number. The algorithm we used in the function was simple: multiply the number by itself. In this section we will reimplement the square function and use a different algorithm, one that relies on addition instead of multiplication.
If you want to multiply two numbers together, the most basic approach is to think of it as repeating the process of adding one number to itself. The number of repetitions is where the second number comes into play. For example, if we wanted to multiply three and five, we could think about it as adding three to itself five times. Three plus three is six, plus three is nine, plus three is 12, and finally plus three is 15. Generalizing this, if we want to implement the idea of squaring a number, call it n, we would add n to itself n times.
Do this by hand first and try to isolate exactly what steps you take. Youโll find you need to keep some โrunning totalโ of the sum so far, either on a piece of paper, or in your head. Remembering things from one step to the next is precisely why we have variables in a program. This means that we will need some variable to remember the โrunning totalโ. It should be initialized with a value of zero. Then, we need to update the โrunning totalโ the correct number of times. For each repetition, weโll want to update the running total by adding the number to it.
In words we could say it this way. To square the value of n, we will repeat the process of updating a running total n times. To update the running total, we take the old value of the โrunning totalโ and add n. That sum becomes the new value of the โrunning totalโ.
Here is the program in activecode. Note that the heading of the function definition is the same as it was before. All that has changed is the details of how the squaring is done. This is a great example of โblack boxโ design. We can change out the details inside of the box and still use the function exactly as we did before.
In the program above, notice that the variable runningtotal starts out with a value of 0. Next, the iteration is performed x times. Inside the for loop, the update occurs. runningtotal is reassigned a new value which is the old value plus the value of x.
This pattern of iterating the updating of a variable is commonly referred to as the accumulator pattern. We refer to the variable as the accumulator. This pattern will come up over and over again. Remember that the key to making it work successfully is to be sure to initialize the variable before you start the iteration. Once inside the iteration, it is required that you update the accumulator.
The variable runningtotal will be reset to 0 each time through the loop. However because this assignment happens as the first instruction, the next instruction in the loop will set it back to x. When the loop finishes, it will have the value x, which is what is returned.
By putting the statement that sets runningtotal to 0 inside the loop, that statement gets executed every time through the loop, instead of once before the loop begins. The result is that runningtotal is โclearedโ (reset to 0) each time through the loop.
The square function will return 0 instead of x * x
The line runningtotal = 0 is the first line in the for loop, but immediately after this line, the line runningtotal = runningtotal + x will execute, giving runningtotal a non-zero value (assuming x is non-zero).
What would happen if we change runningtotal = runningtotal + x to use multiplication instead of addition? Make this change to the program and look at the output.
It is very important to properly initialize the accumulator variable. Do a web search on additive identity and multiplicative identity. Properly initialize the accumulator variable and run the program.
Now we get an answer other than 0. However, the answer is not the square of of x. It is also important that the loop repeat the proper number of times. How many times do we need to execute line 5 to get the square of x? Change line 4 to repeat the correct number of times. Now the program should produce the correct result.