10.12. A histogram¶
It is often useful to take the data from the previous tables and store
them for later access, rather than just print them. What we need is a
way to store 10 integers. We could create 10 integer variables with
names like howManyOnes
, howManyTwos
, etc. But that would require
a lot of typing, and it would be a real pain later if we decided to
change the range of values.
A better solution is to use a vector with size 10. That way we can create all ten storage locations at once and we can access them using indices, rather than ten different names. Here’s how:
int numValues = 100000;
int upperBound = 10;
vector<int> vector = randomVector (numValues, upperBound);
vector<int> histogram (upperBound);
for (int i = 0; i < upperBound; i++) {
int count = howMany (vector, i);
histogram[i] = count;
}
I called the vector histogram because that’s a statistical term for a vector of numbers that counts the number of appearances of a range of values.
The tricky thing here is that I am using the loop variable in two
different ways. First, it is an argument to howMany
, specifying
which value I am interested in. Second, it is an index into the
histogram, specifying which location I should store the result in.
- Vectors require more typing than using individual variables to store data.
- Incorrect! Vectors require less typing than using individual varaibles to store data.
- Vectors create multiple storage locations at once under the same name.
- Correct!
- Once you store something in a vector, you cannot change its value.
- Incorrect! The values of vector elements can always be changed.
- Each storage location of a vector is accessed by indexing.
- Correct!
Q-1: Which of the following statements are true about using vectors to store data?