Wrap-Up Check

Please answer the following questions.

# Here is a short answer question.
# This is the nested dictionary example you will work with.
employee_dict = {
        'John': {'age': 28, 'position': 'Designer',
                'skills': {'soft_skill': 'Creativity',
                           'technical_skill': 'Figma'}},
        'Alice': {'age': 34, 'position': 'Developer',
                'skills': {'soft_skill': 'Communication',
                           'technical_skill': 'Python'}}
    }

# Fill in the missing two lines below to print each employee’s name
# along with their skills using a nested loop.

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        print(f"{name}'s {skill_type_key}: {skill_expertise_value}")

Q-1: - Recommended Time: Spend at most 2 minutes - Put “I am not sure” and click “Save” if unsure of the answer.

For the code piece above, fill in the missing two lines to print each employee’s name along with their skills using a nested loop.

Note: Be sure to indent the second line correctly.

  • Recommended Time: Spend at most 5 minutes - Put “# I am not sure” and click “Save&Run” if unsure of the answer.

Write the function happy_hour_specials(menu_items):

  • menu_items is a list of tuples. Each tuple contains (name, category, is_today_special, price).

  • Return a nested dictionary that only includes the items marked as today’s special (is_today_special is True) and where the prices are less than or equal to 15. Each outer key is the category and each value is a dictionary. The inner dictionary keys are name, and the values are price.

Example Input

Expected Output

happy_hour_specials([("Margherita", "Pizza", True, 15), ("Pepperoni", "Pizza", False, 22), ("Hawaiian", "Pizza", True, 10), ("Caesar", "Salad", True, 10)])

{"Pizza": {"Margherita": 15, "Hawaiian": 10}, "Salad": {"Caesar": 10}}

happy_hour_specials([("Margherita", "Pizza", True, 15), ("Pepperoni", "Pizza", False, 22), ("Olive-Walnut", "Pasta", True, 20), ("Caesar", "Salad", True, 10)])

{"Pizza": {"Margherita": 15}, "Salad": {"Caesar": 10}}

happy_hour_specials([("Lentil", "Soup", True, 15), ("Salmorejo", "Soup", False, 18), ("Harvest", "Salad", False, 18), ("Fruit", "Salad", True, 8)])

{"Soup": {"Lentil": 15}, "Salad": {"Fruit": 8}}

Remember to click ‘Save&Run’ frequently to save your latest answer.

  • Recommended Time: Spend at most 5 minutes - Put “# I am not sure” and click “Save&Run” if unsure of the answer.

Finish the function top_employee(employee_dict) below:

  • The employee_dict is a nested dictionary. The outermost dictionary has unique employee names as keys and a dictionary as values.

  • Each second-level dictionary has keys of age and performance. The value for the key age is a number, the value for the key performance is a dictionary.

  • The performance dictionary has keys of quarters (Q1, Q2, Q3, Q4), and a performance score as the value out of 100.

  • The goal is to return a new dictionary where the keys are the names of top employees (those whose average performance score is above or equal to 90), and the values are their average performance scores.

Example Input

Expected Output

top_employee({"Alice": {"age": 30, "performance": {"Q4": 95}}, "Bob": {"age": 33, "performance": {"Q1": 93, "Q2": 88, "Q3": 95, "Q4": 88}}})

{"Alice": 95, "Bob": 91}

top_employee({"Charlie": {"age": 31, "performance": {"Q3": 70, "Q4": 60}})

{}

top_employee({"Bob": {"age": 33, "performance": {"Q3": 92, "Q4", 92}})

{"Bob": 92}

What to do next

Click on the following link to the final page: Thank you!

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